The mass of 1 atom = Gram atomic mass of atom/ 6.022 × 10 23 So, the mass of 1 atom of oxygen = Gram atomic mass of oxygen atom/ 6.022 × 10 23 = 16g/ 6.022 × 10 23. One mole (not one molecule) of oxygen atoms would weigh 16 g, because an oxygen atom weighs 16 u. To get the mass of an oxygen atom in grams, you'd divide 16 g/mol (well actually 15.999) by Avogadro's number, 6.022×10²³ /mol.
The molar mass ( M ), i.e., the mass of one mole, is equal to the relative atomic (or molecular) mass expressed in grams. So, the unit of measurement of the molar mass is g / mol. The atomic mass and molar mass of oxygen have the same numerical value but different measurement units; for example, a carbon atom weighs 12 u, so the molar mass is. Atomic mass of an element is the relative mass of its atom as compared with the mass of a carbon-12 atom taken as 12 units.Hence, atomic mass of oxygen is 16 u means that one atom of oxygen is 16 times heavier than 1/12 of a carbon-12 atom. 1 mole of H2O = 2 × 6.022×1023 of Hydrogen + 6.022×1023 of Oxygen. To briefly sum up, the mass that belongs to one mole of a substance will be equal to the molecular weight of that substance. For example, 18.015 atomic mass units happens to be water’s molecular weight, and the weight of one mole of water is approximately 18.015 g.
Science >Chemistry >Molecule and Molecular Mass > Calculation of Mass of a Molecule and an Atom
In this article, we shall study the calculation of the mass of molecule and an atom.
Schematic Diagram for Mole Calculations:
Where, m = Given mass, M = Molar mass
v = Given volume, V = Molar volume = 22.4 dm3
n = Number of moles = m/M
Number of atoms = Number of molecules × Atomicity
Conversions:
What is the photo on desktop for mac catalina. To Calculate Mass of Given Moles:
Calculate the mass of the following.
2.5 moles of water:
Molecular mass of water (H2O) = 1 × 2 + 16 × 1 = 2 + 16 = 18 g
Number of moles of water = 2.5 = n
Mass of water = n × Molar mass
Mass of water = 2.5 × 18 = 45 g
1.2 moles of carbon dioxide
Molecular mass of carbon dioxide (CO2) = 12 × 1 + 16 × 2 = 12 + 32 = 44 g
Number of moles of carbon dioxide = 1.2
Mass of carbon dioxide = n × Molar mass
Mass of carbon dioxide = 1.2 × 44 = 52.8 g
0.25 moles of sulphuric acid
Molecular mass of sulphuric acid (H2SO4) = 1 x 2 + 32 x 1 + 16 x 4 = 2 + 32 + 64 = 98 g
Number of moles of sulphuric acid = 0.25 = n
Mass of sulphuric acid = n × Molar mass
Mass of sulphuric acid = 0.25 × 98 = 24.5 g
0.1 moles of ammonia
Molecular mass of ammonia (NH3) = 14 x 1 + 1 x 3 = 14 + 3 = 17 g
Number of moles of ammonia = 0.1 = n
Mass of ammonia = n × Molar mass
Mass of ammonia = 0.1 × 17 = 1.7 g
3.5 moles of methane
Molecular mass of methane (CH4) = 12 x 1 + 1 x 4 = 12 + 4 = 16 g
Number of moles of methane = 3.5 = n
Mass of methane = n × Molar mass
Mass of methane = 3.5 × 16 = 56 g
2.4 moles of sulphur dioxide
Molecular mass of sulphur dioxide (SO2) = 32 x 1 + 16 x 2 = 32 + 32 = 64 g
Number of moles of sulphur dioxide = 2.4 = n
Hamsterball gold level unlockerheremup. Mass of sulphur dioxide = n × Molar mass
Mass of sulphur dioxide = 2.4 × 64 = 153.6 g
0.6 moles of bromine
Molecular mass of bromine (Br2) = 40 x 2 = 80 g
Number of moles of bromine = 0.6 = n
Mass of bromine = n × Molar mass
Mass of bromine = 0.6 × 80 = 48 g
To Calculate Mass of a Molecule and Atom:
Calculate the following
mass of one oxygen atom and oxygen molecule in kg.
Molecular mass of oxygen (O2) = 16 x 2 = 32 g
1 mole of oxygen is 32 g = 32 x 10-3 kg
1 mole of a substance contains 6.022 x 1023 molecules
Mass of each molecule of oxygen = (32 x 10-3)/(6.022 x 1023)
= 5.314 x 10-26 kg
Atomicity of oxygen (O2) molecule is 2
Mass of each atom of oxygen = 5.314 x 10-26 /2 = 2.657 x 10-26 kg
mass of one calcium atom in kg.
Molecular mass of calcium (Ca) = 40 g
1 mole of calcium is 40 g = 40 x 10-3 kg
1 mole of a substance contains 6.022 x 1023 molecules
Mass of each molecule of calcium = (40 x 10-3)/(6.022 x 1023)
= 6.642 x 10-26 kg
Atomicity of calcium (Ca) molecule is 1
Mass of each atom of calcium = 6.642 x 10-26 /1 = 6.642 x 10-26 kg
mass of one nitrogen atom and nitrogen molecule in kg.
Molecular mass of nitrogen (N2) = 14 x 2 = 28 g
1 mole of nitrogen is 28 g = 28 x 10-3 kg
1 mole of a substance contains 6.022 x 1023 molecules
Mass of each molecule of nitrogen = (28 x 10-3)/(6.022 x 1023)
= 4.650 x 10-26 kg
Atomicity of nitrogen (N2) molecule is 2
Mass of each atom of nitrogen = 4.650 x 10-26 /2 = 2.325 x 10-26 kg
mass of one sulphur dioxide molecule in grams.
Molecular mass of sulphur dioxide (SO2) = 32 x 1 + 16 x 2 = 64 g
1 mole of sulphur dioxide is 64 g
1 mole of a substance contains 6.022 x 1023 molecules
Mass of each molecule of sulphur dioxide = (64)/(6.022 x 1023)
= 1.602 x 10-22 kg
mass of 100 molecules of water.
Molecular mass of water (H2O) = 1 x 2 + 16 x 1 = 18 g
1 mole of water is 18 g = 18 x 10-3 kg
1 mole of a substance contains 6.022 x 1023 molecules
Mass of each molecule of water = (18 x 10-3)/(6.022 x 1023) = 2.989 x 10-26 kg
Mass of 100 molecules of water = 2.989 x 10-26 x 100 = 2.989 x 10-24 kg
Calculation of Volume at STP
Calculate the volume of following at STP.
8.5 x 10-4 kg of ammonia
Molecular mass of ammonia (NH3) = 14 x 1 + 1 x 3 = 14 + 3 = 17 g
= 17 x 10-3 kg
Number of moles of ammonia = given mass/ molecular mass
= (8.5 x 10-4)/(17 x 10-3) = 0.05
1 mol of a gas at STP occupies 22.4 dm3 by volume
Volume of ammonia = number of moles x 22.4
Volume of 8.5 x 10-4 kg of ammonia at STP = 0.05 x 22.4 = 1.12 dm3
3.5 x 10-3 kg of nitrogen
Molecular mass of nitrogen (N2) = 14 x 2 = 28 g = 28 x 10-3 kg
Number of moles of nitrogen = given mass/ molecular mass
= (3.5 x 10-3)/(28 x 10-3) = 0.125
1 mol of a gas at STP occupies 22.4 dm3 by volume
Volume of nitrogen= number of moles x 22.4
Volume of 3.5 x 10-3 kg of nitrogen at STP = 0.125 x 22.4 = 2.8 dm3
14 g of nitrogen
Molecular mass of nitrogen (N2) = 14 x 2 = 28 g = 28 x 10-3 kg
Number of moles of nitrogen = given mass/ molecular mass
= (14 x 10-3)/(28 x 10-3) = 0.5
1 mol of a gas at STP occupies 22.4 dm3 by volume
Is Oxygen A Atom
Volume of nitrogen= number of moles x 22.4
Volume of 3.5 x 10-3 kg of nitrogen at STP = 0.5 x 22.4 = 11.2 dm3
6.023 x 1022 molecules of ammonia
Number of moles of ammonia = Given molecules/ Avogadro’s number
Number of moles of ammonia = (6.023 x 1022)/(6.023 x 1023) = 0.1
1 mol of a gas at STP occupies 22.4 dm3 by volume
Volume of ammonia = number of moles x 22.4
Volume of 6.023 x 1022 molecules of ammonia at STP = 0.1 x 22.4 = 2.24 dm3
2.008 x 1023 molecules of SO2 at STP.
Number of moles of SO2 = Given molecules/ Avogadro’s number
Number of moles of SO2 = (2.008 x 1022)/(6.023 x 1023) = 0.3334
1 mol of a gas at STP occupies 22.4 dm3 by volume
Volume of SO2 = number of moles x 22.4
Volume of 2.008 x 1023 molecules of SO2 at STP = 0.3334 x 22.4 = 7.469 dm3
0.2 mole of sulphur dioxide.
1 mol of a gas at STP occupies 22.4 dm3 by volume
Volume of sulphur dioxide = number of moles x 22.4
Volume of 0.2 moles of sulphur dioxide at STP = 0.2 x 22.4 = 4.48 dm3
Science >Chemistry >Molecule and Molecular Mass > Calculation of Mass of a Molecule and an Atom
Anand Singh answered this
Dear Student,
1. The mass of 1 atom = Gram atomic mass of atom/ 6.022 × 1023
So, the mass of 1 atom of oxygen = Gram atomic mass of oxygen atom/ 6.022 × 1023 Ncaa football 12.
= 16g/ 6.022 × 1023
= 2.66 × 10-23 g
Due to time constraint, it would not be possible for us to provide the answers to all your queries. We are some trick to solve rest questions. Try solving rest of the questions yourself and if you face any difficulty then do get back to us.
Let use an idea to solve this and your other questions
- First learn the mole concept table as
| Mole Relationship | 1 Mole | 6.022 × 1023 | 22.4 L at STP | Gram Atomic Mass-GAM | Gram Molecular Mass-GMM |
| Categories | No of moles | No of particles | Volume | Mass | mass |
- Use the follwing calculation box
| To find | Given data in question |
| Reapective value from mole concept table | Reapective value from mole concept table |
Now solve the Ist question again.
- Let the mass of 1 oxygen atom = X g (put this into the To find of calculation box) i.e. we want to find mass.
- So, reapective value from mole concept table is mass i.e GAM which is 16g. (put this into the below of To find of calculation box)
- Given no of atom is 1. (put this into the Given data in question of calculation box). It is no. of particle.
- So, reapective value from mole concept table is no. of particles i.e. 6.022 × 1023 (put this into the below of Given data in question of calculation box).
Let the mass of 1 atom of oxygen = Xg
| To find = Xg | Given data in question= 1 |
| Reapective value from mole concept table = GAM=16 | Reapective value from mole concept table= 6.022 × 1023 |
so, X/16 = 1/ 6.022 × 1023
X = 1×16 / 6.022 × 1023
= 2.66 × 10-23 g
Hence, the mass of 1 atom of oxygen = 2.66 × 10-23 g
Hope! This would help you.
Adithya .f. Uday answered this
9.by using the formula ,
mass of an atom = atomic mass
avagardo number
atomic mass =mass of atom * 6.022*1023
=2*10-23*6.022*1023
=12.044 ,
Oxygen Atom Model
the element X could be carbon
Mass Of Oxygen In Kg
sam56 answered this